Question

Resolver los siguientes cálculos con polinomios
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Answer 1

Hola!

Respuesta:

$= \frac{1}{4} {x}^{3} ( 1- 7 {x}^{3} )$

Explicación paso a paso:

a)

${( \frac{1}{4} + \frac{1}{2} {x}^{3}) }^{2} + (x - 2 {x}^{2} ). {x}^{4} - ( {x}^{5} + \frac{1}{6} ) = \\ \\ = \frac{1}{16} + \frac{1}{4} {x}^{3} + \frac{1}{4} {x}^{6} + {x}^{5} - 2 {x}^{6} - {x}^{5} - \frac{1}{6} \\ = \frac{1}{4} {x}^{3} + \frac{1}{4} {x}^{6} - 2 {x}^{6} \\ = \frac{1}{4} {x}^{3} - ( 2 - \frac{1}{4} ) {x}^{6} \\ = \frac{1}{4} {x}^{3} - \frac{7}{4} {x}^{6} \\ = \frac{1}{4} {x}^{3} ( 1- 7 {x}^{3} )$