Question

Resolver: (log(2x(2 )+3x+12) / (log (2x+3)=2

Answer 1

Respuesta:

$x=\frac{-5+\sqrt{7\\3} }{8}$

Explicación paso a paso:

$(log(2x(2)+3x+12)/ (log(2x+3)=2$

$\frac{log10(2x.2+3x+12)}{(log10(2x+3)} long10(2x+3)=2log10(2x+3)$

$log10(7x+12)=2log10(2x+3)$

$7x+12=(2x+3)^{2}$

$x=\frac{-5+\sqrt{73} }{8}, x=\frac{-5-\sqrt{73} }{8}$

$x= \frac{-5+\sqrt{73} }{8}$