Question

Resolver las sumas algebraicas
A) √48 + √27
B) √12 + √27

Answer 1

$a) \sqrt{48} +\sqrt{27} = 7\sqrt{3} \\\sqrt{48} = \sqrt{16x3} = 4\sqrt{3} \\\\\\\\\sqrt{27} =\sqrt{9x3} =3\sqrt{3} \\b)\sqrt{12} +\sqrt{27} =5\sqrt{3} \\\sqrt{12} =\sqrt{4x3} =2\sqrt{3} \\\sqrt{27} =\sqrt{9x3} =3\sqrt{3}$