Question

RESOLVER LAS SIGUIENTES ECUACIONES
1. 3x+5=5x-13
2. 5(7-x)=31-x
3. 4(2-3x)= -2x-27
4. 6x-8=4(-2x+5)
5. 3(4x+7)=4x-25
6. 7x+15=3(3x-7)

Answer 1

1. 3x-5x=-13-5 / -2x=-18/ x=9

2.35-5x =31-x / -5x+x= 31-35/ -4x=-4 / x=1

3.8-12x=-2x-27 /-12x+2x=-27-8 /-10x=-35 / x=-3.5

4. 6x-8=-8x+20 / 6x+8x=20+8 / 14x=28 / x=2

5.12x+21=4x-25/ 12x-4x =-25-21 / 8x= -46 / x=-5.75

6. 7x+15=9x-21 / 7x-9x=-21-15 / -2x=-36/ x=18

Answer 2

1.

$3x + 5 = 5x - 13 \\ 13 + 5 = 5x - 3x \\ 13 + 5 = 2x \\ 18 = 2x \\ \frac{18}{2} = x \\ x = 9$

2.

$5(7 - x) = 31 - x$
En la primera parte debemos multiplicar:

5 × 7 y 5 × -x:

$35 - 5x = 31 - x \\ 35 - 31 = - x + 5x \\ 4 = 4x \\ \frac{4}{4} = x \\ 1 = x$
3.

$4(2 - 3x) = - 2x - 27 \\ 8 - 12x = - 2x - 27 \\ 8 + 27 = - 2x + 12x \\ 35 = 10x \\ \frac{35}{10} = x \\ 3.5 = x$

4.

$6x - 8 = 4( - 2x + 5) \\ 6x - 8 = - 8x + 20 \\ 6x + 8x = 20 + 8 \\ 14x = 28 \\ x = \frac{28}{14} \\ x = 2$

5.

$3(4x + 7) = 4x - 25 \\ 12x + 21 = 4x - 25 \\ 12x - 4x = - 25 - 21 \\ 8x = - 46 \\ x = \frac{ - 46}{8} \\ x = - 5.75$

6.

$7x + 15 = 3(3x - 7) \\ 7x + 15 = 9x - 21 \\ 21 + 15 = 9x - 7x \\ 36 = 2x \\ \frac{36}{2} = x \\ 18 = x$
Espero haberte ayudado,
SALUDOS CORDIALES, AspR178!!!! ;)

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