Question

Resolver las ecuaciones aplicando propiedades uniforme y cancelativa

a) 7x + 4 = 2x + 19 b) 3x – 4 =x c) 5x – 9 + x = 15 + 3x d) X +1 + 6x = 29 e) 7 + 8x = x + 28 + 4x f) 4 + 7 = 3x + 23 g) 5x + 7 = 2x + 25 h) 7x – 20 = 2x + x i) x : 4 – 9 = 63 j) 8x – 5 = 5x + 13 k) 8 x : 5= 43

Answer 1

a) 7x + 4 = 2x + 19

7x - 2x = 19 - 4

5x = 15

x = 3

b) 3x – 4 =x

3x - x = 4

2x = 4

x = 2

c) 5x – 9 + x = 15 + 3x

5x + x - 3x = 15 + 9

3x = 24

x = 8

d) x + 1 + 6x = 29

7x = 29 - 1

7x = 28

x = 4

e) 7 + 8x = x + 28 + 4x

8x - x - 4x = 28 - 7

3x = 21

x = 7

f) 4 + 7 = 3x + 23

3x = -23 + 7 + 4

3x = -12

x = -4

g) 5x + 7 = 2x + 25

5x - 2x = 25 - 7

3x = 18

x = 6

h) 7x – 20 = 2x + x

7x - 2x - x = 20

4x = 20

x = 5

i) x : 4 – 9 = 63

x : 4 = 63 + 9

x : 4 = 72

x = 288

j) 8x – 5 = 5x + 13

8x - 5x = 13 + 5

3x = 18

x = 6

k) 8x : 5 = 43

8x = 215

x = 215/8

Answer 2

Respuesta:

m

Explicación paso a paso: