Question

Resolver la siguiente división algebraica de polinomios
(32-46a^2+11a^3-3a^5 )÷ (8-6a-3a^2)

Answer 1

Respuesta:

(32-46a^2+11a^3-3a^5 )÷ (8-6a-3a^2)

$=a^3+\frac{6a^4+3a^3-46a^2+32}{-3a^2-6a+8}\\\\\\=a^3-2a^2+\frac{-9a^3-30a^2+32}{-3a^2-6a+8}\\\\\\=a^3-2a^2+3a+\frac{-12a^2-24a+32}{-3a^2-6a+8}\\\\\\=a^3-2a^2+3a+4$