Question

RESOLVER LA INECUACION X^4+12X^2-64X^2>0

Answer 1

Explicación paso a paso:

(x4+12x3-64x2)≥0  

Reformatting the input :

Changes made to your input should not affect the solution:

(1): "x2"   was replaced by   "x^2".  2 more similar replacement(s).

Step by step solution :

Step  1  :

Equation at the end of step  1  :

((x4) +  (12 • (x3))) -  26x2  ≥ 0  

Step  2  :

Equation at the end of step  2  :

((x4) +  (22•3x3)) -  26x2  ≥ 0  

Step  3  :

Step  4  :

Pulling out like terms :

4.1     Pull out like factors :

x4 + 12x3 - 64x2  =   x2 • (x2 + 12x - 64)  

Trying to factor by splitting the middle term

4.2     Factoring  x2 + 12x - 64  

The first term is,  x2  its coefficient is  1 .

The middle term is,  +12x  its coefficient is  12 .

The last term, "the constant", is  -64  

Step-1 : Multiply the coefficient of the first term by the constant   1 • -64 = -64  Step-2 : Find two factors of  -64  whose sum equals the coefficient of the middle term, which is   12 .

       -64    +    1    =    -63  

     -32    +    2    =    -30  

     -16    +    4    =    -12  

     -8    +    8    =    0  

     -4    +    16    =    12    That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -4  and  16  

                    x2 - 4x + 16x - 64

Step-4 : Add up the first 2 terms, pulling out like factors :

                   x • (x-4)

             Add up the last 2 terms, pulling out common factors :

                   16 • (x-4)

Step-5 : Add up the four terms of step 4 :

                   (x+16)  •  (x-4)

            Which is the desired factorization

Equation at the end of step  4  :

 x2 • (x + 16) • (x - 4)  ≥ 0  

Step  5  :

Run Time Error 78: Non Linear Inequality not implemented yet

Program Terminated

Tiger was not able to solve for your input:(x4+12x3-64x2)>=0

espero que te sirva