Question

Resolver esta funcion cuadratica 1,5x^2-0,5x=0

Answer 1

a= 1,5
b=-0,5
c=0

Δ=(-0.5)-4(1.5)(0)

Δ=-$\frac{1}{2}$
x= $\frac{-b+- \sqrt{ b^{2} -4ac} }{2a}$

$x_{1}$=-$\frac{1}{3}$
$x_{2}$=0