Question

Resolver el siguiente ejercicionpor metodo de sustitucion x+y=3 2×+3y=5

Answer 1

x+y= 3 [1 ]
2x+3y= 5 [2]
despejar x en [1]
x+y=3
x= 3-y [3]
sustituir [3] en [2]
2x + 3y=5
2(3-y)+3y=5
6-2y+3y=5
y=5-6
y=1 [4]
sustituir [4] en [3]
x= 3-y
x= 3-(-1)
x=3+1
x=4

Rpta:(-1;4)