Question

resolver cada una de las ecuaciones cuadráticas usando la formula general
2x2+2x=5x
48+2x=x2
x2-6x=7
x2-10x+25=0

Answer 1

Explicación:

1. 2x2+2x=5x

2x2+2x-5x= 0

x (2x+2-5)=0

x (2x-3)=0

x=0

2x-3=0

x=0

x= 3/2

x1= 0 x2= 3/2

2. 48+2x=x2

48+2x-x2=0

-x2+2x+48=0

x2-2x-48=0

x=-(-2)+-raiz (-2)2-4(1)(-48)/2 (1)

x= 2+-raiz 4+192/2

x= 2+-raiz 196/2

x=2+-14/2

x=2+14/2

x=2-14/2

x= 8

x= -6

x1= 8 x2= -6

3. x2-6x=7

x2-6x-7=0

x= (-6)+-raiz(-6)2-4 (1)(-7)/2 (1)

x= 6+-raiz 36+28/2

x=6+-raiz 64/2

x= 6+-8/2

x=6+8/2

x=6-8/2

x= 7

x= -1

x1=7 x2= -1

4. x2-10x+25=0

(x-5)2 = 0

x2-10+25=0

(x-5)2=0

x-5=0

x=5

espero averte ayudadoo...