Question

resolver aplicando propiedades
2√50 × 3√2=

√1/6 × 3√2=

√-12 : √-3=

√2 × (√8-√50 ) =

(√12 - √75) : √3=

(3+√1/3) × (3-√1/3) =

(3+ √2)2

Answer 1

2√50 × 3√2=  $(10 \sqrt{2}) (3 \sqrt{2}) = 30 \sqrt{4} = 30(2) = 60$

√1/6 × 3√2= $(\frac{ \sqrt{6} }{6} )(3 \sqrt{2} ) = \frac{6 \sqrt{3} }{6} = \sqrt{3}$

√-12 : √-3= $\frac{ \sqrt{-12} }{ \sqrt{-3} } = \sqrt{ \frac{12}{3} } = \sqrt{4} = 2$

√2 × (√8-√50 ) = $( \sqrt{2} )( \sqrt{8} - \sqrt{50} ) = \sqrt{2} (2 \sqrt{2} - 5 \sqrt{2} ) = \sqrt{2}(-3 \sqrt{2} ) = 2(-3) = -6$