Question

resolver: 2(3-x)+x-5=x+6-x/3. hallar: x²

Answer 1

Respuesta:

2(3-x)+x-5 = x+6-(x/3)

6-2x+x-5 = x+6-x/3

6-x-5 = (1-1/3)x+6

1-x = (2/3)x+6

1-x+x = (2/3)x+6+x

1 = (2/3+1)x+6

1 = (5/3)x+6

1-6 = (5/3)x+6-6

-5 = (5/3)x

3(-5) = 3(5/3)x

-15 = (15/3)x

-15 = 5x

-15/5 = 5x/5

-3 = x

x = -3

Comprobación :

2(3-(-3))+(-3)-5 = (-3)+6-((-3)/3)

2(3+3)-3-5 = -3+6-(-1)

2(6)-8 = -3+6+1

12-8 = -3+7

4 = 4

X vale -3

Se halla x² :

x² ; x = -3

x² = (-3)²

x² = 9

R// x² vale 9

Explicación paso a paso: