Question

resolver : 10^2-log(x+y)=25, hallar: x+y​

Answer 1

Explicación paso a paso:

Para x ->

100−log(x+y)=25

−log(x+y)=25−100

−log(x+y)=−75

log(x+y)/1=−75/−1

log(x+y)=−75/−1

log(x+y)=75

10^75=x+y

x+y=10^75

x=10^75−y

Para y->

10^2log(x+y)/10^2=25/10^2

log(x+y)=25/10^2

log(x+y)=1/4

10^1/4=x+y

x+y=10^1/4

y=10^1/4−x