Question

Resolver :
1/(x-2) +(x/3) =2

Answer 1

Respuesta:

$x_{1}$ = 3    $x_{2}$ = 5

Explicación paso a paso:

1/(x-2) +(x/3) =2

1/(x-2) +(x/3) = - 2

$\frac{3+x*(x-2)-6(x-2)}{3(x-2)} = 0$

$\frac{3+x^{2}-2x-6x+12 }{3(x-2)} =0$

$\frac{15+x^{2}-8x }{3(x-2)} =0$

15 + $x^{2}$ - 8x = 0

$x^{2}$ - 8x + 15 = 0

$x^{2}$ - 3x - 5x + 15 = 0

x * (x-3) - 5 (x-3) = 0

(x-3) * (x-5) = 0

x-3 = 0

x-5 = 0

$x_{1}$= 3

$x_{2}$ = 5

espero te sirva saludos.....