Question

RESOLIVER EL SISTEME POR METODO DE REDUCCION
X+2Y+3Z=7
2X+2Y-4Z=-2
3X-Y+Z=8

Answer 1

Respuesta:

Explicación paso a paso:

$X+2Y+3Z=7\\\\X+2Y+3Z-\left(2Y+3Z\right)=7-\left(2Y+3Z\right)\\\\X=7-2Y-3Z$

$2X+2Y-4Z=-2\\\\2X+2Y-4Z-\left(2Y-4Z\right)=-2-\left(2Y-4Z\right)\\\\2X=-2-2Y+4Z\\\\\frac{2X}{2}=-\frac{2}{2}-\frac{2Y}{2}+\frac{4Z}{2}\\\\X=-1-Y+2Z$

$3X-Y+Z=8\\\\3X-Y+Z-\left(-Y+Z\right)=8-\left(-Y+Z\right)\\\\3X=8+Y-Z\\\\\frac{3X}{3}=\frac{8}{3}+\frac{Y}{3}-\frac{Z}{3}\\\\X=\frac{8+Y-Z}{3}$