Question

repuesta . resuelve la ecuaciones

3× = 12

3×-5=0

×+4=17

2×4=0

2×+1=3

3×+8=24

9y-3=21

5 (z-12)=27

5 (y-17)=2 (y-3)

2×-16=34×

3 (×+5)-2×=3-(4y-2)

2×-10=6×+8

12=6 (×+1)-8 (1-×)

15×-18=27

8 (×-8)=24​

Answer 1

Respuesta:

3× = 12

3×-5=0

×+4=17

2×4=0

2×+1=3

3×+8=24

9y-3=21

5 (z-12)=27

5 (y-17)=2 (y-3)

2×-16=34×

3 (×+5)-2×=3-(4y-2)

2×-10=6×+8

12=6 (×+1)-8 (1-×)

15×-18=27

8 (×-8)=24