Question

reducir: (x+4) (x2 - 4x + 16) + (x-4) ( x2 +4x + 16 )
reducir (x-4) (x2 + 4x +16 ) - ( x-1) ( x2 + x + 1)
efectuar (5+y) (5+3y) - (2+3y) (2-5y) + 12 (y+1) (y-1) -9

Answer 1

(x-4) (x2 + 4x +16 ) - ( x-1) ( x2 + x + 1)
x³+4x²+16x-4x²-16x-64-(x³+x²+x-x²-x-1)
x³-64-x³+1
-63


(5+y) (5+3y) - (2+3y) (2-5y) + 12 (y+1) (y-1) -9
25+15y+5y+3y²-(4-10y+6y-15y²)+12(y²-1)-9
25+20y+3y²-4+4y+15y²+12y²-12-9
30y²+24y

Answer 2

2010101010101010101010101

x4