Question

reducir: (2x+1)²+(2x-3)²-8x(x-1)​

Answer 1

Respuesta:

Since this is a difference of squares, we can expand it.

(2x+1)²-(2x-3)²=-8x(x-1)

4x²+4x+1-4x²+12x-9=-8x(x-1)

4x+4-12x+9=-8x(x-1)

-8x+13=-8x(x-1)

-8x+13=-8x²+8x

-8x+13=8x-8x²

-8x²+21x-13=0

-8x²+24x-21x+13=0

-8x²+21x-13=0

-8x²+3x(7)-13=0

-8x²+3x(7)-39=0

-8x²+21x-39=0

-8x²+21x-39=0

-8x²+3x(7)-39=0

-8x²+21x-39=0

I'm not sure if my help was helpful...