Question

reducir

25a³b+12a²b-18a3+5a³b-46a3b-28a³b

3/10a³-4/5a³+2/9³-4/9a³-1 1/2a³+7/8a³

0.7ab²+0.465ab²-1.8ab²-3.4ab²+0.15ab​

Answer 1

a)

$25a³b+12a²b-18a3+5a³b-46a3b-28a³b$

$(25 + 5 - 28) {a}^{3} b + 12 {a}^{2}b - 18a \times 3 - 46a \times 3b$

$2 {a}^{3} b + 12{a}^{2} b - 54a - 138ab$

b)

$\frac{3}{10 } {a}^{3} - \frac{4}{5} a {}^{3} + \frac{2}{9 {}^{3} } - \frac{4}{9} {a}^{3} - \frac{11}{2} {a}^{3} + \frac{7}{8} {a}^{3}$

$( \frac{3}{10} - \frac{4}{5} - \frac{4}{9} - \frac{11}{2} + \frac{7}{8} ) {a}^{3} + \frac{2}{ {9}^{3} }$

$- \frac{401}{72} {a}^{3} + \frac{2}{9 \times 9 \times 9}$

$- \frac{401}{72} {a}^{3} + \frac{2}{729}$

c)

$0.7a {b}^{2} + 0.465a {b}^{2} - 1.8a {b}^{2} - 3.4a {b}^{2} + 0.15ab$

$\frac{7}{10} a {b}^{2} + \frac{93}{200} a {b}^{2} - \frac{9}{5} a {b}^{2} - \frac{17}{5} a {b}^{2} + \frac{3}{20} ab$

$( \frac{7}{10} + \frac{93}{200} - \frac{9}{5} - \frac{17}{5} )a {b}^{2} + \frac{3}{20}ab$

$- \frac{807}{200} a {b}^{2} + \frac{3}{20} ab$