Question

Reduce:
P = (Secx – Cosx) Cscx

Answer 1

${(\sec x-\cos x)\csc x=}\\\\{\left(\frac{1}{\cos x}-\cos x\right)\csc x=}\\\\{\left(\frac{1-\cos^2x}{\cos x}\right)\csc x=}\\\\{\dfrac{\sin^2x}{\cos x}.\dfrac{1}{\sin x}=}\\\\\\{\dfrac{\sin x}{\cos x}=}\\\\\\{\boxed{\tan x}}$