reduce c=sen2x.secx+cscx
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Respuesta:
\begin{gathered}{(\sec x-\cos x)\csc x=}\\\\{\left(\frac{1}{\cos x}-\cos x\right)\csc x=}\\\\{\left(\frac{1-\cos^2x}{\cos x}\right)\csc x=}\\\\{\dfrac{\sin^2x}{\cos x}.\dfrac{1}{\sin x}=}\\\\\\{\dfrac{\sin x}{\cos x}=}\\\\\\{\boxed{\tan x}}\end{gathered}
(secx−cosx)cscx=
(
cosx
1
−cosx)cscx=
(
cosx
1−cos
2
x
)cscx=
cosx
sin
2
x
.
sinx
1
=
cosx
sinx
=
tanx
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