Question

racionalice 2/(√2-√3)

Answer 1

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Answer 2

$\frac{2}{ \sqrt{2} - \sqrt{3} }= \frac{2}{ \sqrt{2} - \sqrt{3} } . \frac{ \sqrt{2} + \sqrt{3}}{ \sqrt{2} + \sqrt{3}}$

$\frac{2}{ \sqrt{2} - \sqrt{3} }= \frac{2( \sqrt{2} + \sqrt{3})}{(\sqrt{2})^2 - (\sqrt{3})^2}$

$\frac{2}{ \sqrt{2} - \sqrt{3} }= \frac{2( \sqrt{2} + \sqrt{3})}{2-3}$

$\frac{2}{ \sqrt{2} - \sqrt{3} }=- {2( \sqrt{2} + \sqrt{3})}$