Question

r(y)=(1+2t)i+(t^2-2t)j

Answer 1

Respuesta:

$y=\frac{jt^2-2jt}{r}+i\frac{1+2t}{r};\quad \:r\ne \:0$

Explicación:

$=\frac{i\left(2t+1\right)+j\left(t^2-2t\right)}{r}$

$=\frac{jt^2-2jt}{r}+\frac{1+2t}{r}i$

$y=\frac{jt^2-2jt}{r}+i\frac{1+2t}{r};\quad \:r\ne \:0$