Question

química 7.5 de KNO3 en 505 ml de solución

Answer 1

supongo que calcular molaridad

v = 500 mL / 0.5 L
Mm (KNO3) = 101 g/mol

n (moles) = masa / Mm
n = 7.5 g /101 g/mol = 0.074 moles

M = 0.074 moles / 0.5 L = 0.148 mol/L

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% V/V =V soluto / vsolución x 100

% v/v = 7.5 / 500 x 100

% v/v = 1.5 % mL / mL