Question

Quien me ayuda por favor

Answer 1

Respuesta:

por factorizacion

${x}^{2} + 6x + 8 = 0 \\ (x + 4)(x + 2)$

${x}^{2} - 9x - 14 = 0 \\ (x - 7)(x - 2)$

ecuacion general

$\frac{- b + - \sqrt[2]{ {b}^{2} - 4ac } } {2a}$

para

${x}^{2} + 6x + 8 \\ a = 1 \\ b = 6 \\ c = 8$

$\frac{- 6 + - \sqrt[2]{ {6}^{2} - 4(1)(8) } } {2(1)} \\ \\ \frac{- 6 + - \sqrt[2]{ 36 - 32 } } {2} \\ \\ \frac{ - 6 (+ -) 2}{2}$

calculamos X1 y X2

$x1 = \frac{ - 6 + 2}{2} = \frac{ - 4}{2} \\ x1 = - 2$

$x2 = \frac{ - 6 - 2}{2} = - \frac{-8}{2} \\ \\ x2 = - 4$

para

${x}^{2} + 6x + 8 \\ a = 1 \\ b = -9 \\ c = -14$

$\frac{- (-9) + - \sqrt[2]{ {(-9)}^{2} - 4(1)(-14) } } {2(1)} \\ \\ \frac{- (-9) + - \sqrt[2]{ 81 + 56 } } {2} \\ \\ \frac{ 9 (+ -) 11.70}{2}$

calculamos X1 y X2

$x1 = \frac{ 9 + 11.70}{2} = \frac{ 20.70}{2} \\ x1 = 10.35$

$x2 = \frac{ 9 - 11.70}{2} = - \frac{2.70}{2} \\ \\ x2 = - 1.35$