Question

quien me ayuda por favor

Answer 1

$4x+\frac{2}{3}\left(x-4-\frac{4}{6}\left(4-3x\right)\right)=\frac{2}{3}\left(1-\frac{5x}{2}\right)$
$4x+\frac{2\left(x-4-\frac{2}{3}\left(4-3x\right)\right)}{3}=\frac{2}{3}\left(1-\frac{5x}{2}\right)$
$\frac{54x-40}{9}=\frac{2-5x}{3}$
$\frac{54x-40}{9}\cdot \:9=\frac{2-5x}{3}\cdot \:9$
$54x-40=3\left(2-5x\right)$
$54x-40=6-15x$
$54x-40+40=6-15x+40$
$54x=-15x+46$
$54x+15x=-15x+46+15x$
$69x=46$
$\frac{69x}{69}=\frac{46}{69}$
$x=\frac{2}{3}$