Question

quien lo aga bien le doy corona es arimetica

Answer 1

Respuesta:

1R:

a) (12/13)^2= 12^2/13^2= 144/169

b) (3/2)^5= 3^5/2^5= 243/32

2R:

a) (1/4)^-2= 4^2=16

b) (2/5)^-1= 5/2

3R:

a) [(1/6)^4÷(1/6)^2]^2= [(1/6)^2]^2= (1/6)^4= 1/1296

b) [(2/7)^3×(2/7)^2]^2= [(2/7)^5]^2= (2/7)^10

Answer 2

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