Question

que volumen ocuparan 15.0g de kripton a 80°C y 725 mmHg

Answer 1

P= 725mmHg

n = 15.0gKr×1molKr/83gKr= 0.180molKr

R= 62.4mmHg×L/°K×mol

T= 80°C + 273 = 353°K

PV=nRT

V=nRT/P

V=0.180mol*62.4mmHg×L/°K×mol×353°K/725mmHg = 5.47 L