Question

Que volumen ocupara 100 gramos de argon a 80°C y 780 torr​

Answer 1

Respuesta:V· P = n · R · T   (Ley de los gases ideales)

V = ?

P = 780 mmHg / 760 = 1.026 atm

T = 80 ºC + 273 = 353 K

m = 0.2 lb

g = lb  x  453.59

g = 0.2 x 453.59 = 90.718 g

R = 0.0821 (L atm / mol K)

Mm Ar = 39.94g/mol

1. calcular mol  mol = masa/Mm

mol = 90.718 g / 39.94 g/mol

mol = 2.271

2. calcular volumen  (ley de los gases ideales)

V · P = n · R · T  despejar volumen

V =  2.271 mol   ·   0.0821 (L atm / mol K)  ·  353 K

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                                  1.026 atm

V = 64.14 L

creo que seria asi espero te ayude