¿ Que volumen ocupan 8.5 moles de un gas que se encuentra a 300 K y 1 ATM de presión ?
Respuestas a la pregunta
Contestado por
5
P V = n R T
P = 1 atm
T= 300 K
V = ?
n = 8.5 moles
R= 0.0821 (L atm / mol K)
V = n R T
````````
P
V = 8.5 moles x 0.0821 (L atm / mol K) x 300 K
````````````````````````````````````````````````````````````
1 atm
V = 209.36 L
P = 1 atm
T= 300 K
V = ?
n = 8.5 moles
R= 0.0821 (L atm / mol K)
V = n R T
````````
P
V = 8.5 moles x 0.0821 (L atm / mol K) x 300 K
````````````````````````````````````````````````````````````
1 atm
V = 209.36 L
Otras preguntas