Question

que sea con proceso xfa

Answer 1

Respuesta: 1.-620, 2.-405 ,3.-3,528 ,4.-201 ,5.-  -26

1.- $25^{2}+\sqrt{169}-\sqrt{256}$

625+13-18

638-18= 620

2.-{${\sqrt{169}*4-[6^{2} -(5+2^3*3)]}$}$*3^{2}$

{13*4-[36-(5+8*3]}*9

{13*4-[36-(5+24]}*9

{52-[36-(5+24]}*9

{52-[36-29]}*9

{52-7}*9

45*9= 405

3.- {$3(5^{2}-\sqrt{16})*2^{2}$}*$(2\sqrt{49} )$

{3(25-4)*4}*14

{3(21)*4}*14

{63*4}*14

252* 14= 3,528

4.- $12+3*5*15-\sqrt{16} \sqrt{9}$

12+3*5*15-4*9

12+225-36

237-36= 201

5.-$\sqrt{25} +\sqrt{1}-1^{0}*2^{3}*2^{2}$

5+1-$1^{0}* 2^{3}* 2^{2}$

5+1-1*8*4

5+1-32

6-32=  -26

Explicación paso a paso: Espero te sirva salu3