que presión ejercen 0.46 g de O2 a la temperatura de 42°C, ocupando un volumen de 15ml
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LEY DE LOS GASES IDEALES: V P = n R T
V = 15 mL / 1000 = 0.015 L
P= ?
m = 0.46 g de O2
Mm O2 = 32 g/mol
R = 0.0821 (L a tm / mol K)
T = 42 ºC + 273 = 315 K
1. CALCULAR n (moles)
n = masa/Mm
n = 0.46 g / 32 g/mol
n = 0.0144 mol
2. calcula P
P = 0.0144 mol x 0.0821 (L atm/ mol K) x 315 K
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0.015 L
P = 24.82 atm.
V = 15 mL / 1000 = 0.015 L
P= ?
m = 0.46 g de O2
Mm O2 = 32 g/mol
R = 0.0821 (L a tm / mol K)
T = 42 ºC + 273 = 315 K
1. CALCULAR n (moles)
n = masa/Mm
n = 0.46 g / 32 g/mol
n = 0.0144 mol
2. calcula P
P = 0.0144 mol x 0.0821 (L atm/ mol K) x 315 K
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0.015 L
P = 24.82 atm.
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