Question

¿que peso de hidrogeno se necesita para formar 136 gramos de amoniaco !

Answer 1

N2 + 3 H2 → 2 NH3

Mm NH3 = 17 g/mol

H2 = 2 g/mol

calcular gramos de H2

g H2 = 136 g NH3 x 1 mol NH3 x 3 mol H2 x 2 g H2

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17 g NH3 2 mol NH3 1 mol NH3

g H2 = 24