que pesa mas 20 lts de cloro a 800mmHg y 26ºC o 40 lts de CO2 a 778 mmHg y a 31ºC? el peso molecular del cloro 71 gr/mol y del CO2= 44 gr/mol
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Ley de los gases ideales: V x P = n x R x T
CLORO: Cl2
V = 20 L
P = 800 mmHg = 1.052 atm.
R = 0.0821 ( L atm / mol K)
T = 26 ºC + 273 = 299 K
n = ?
n = 20 L x 1.052 atm
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0.0821 (Latm/mol K) x 299 K
n = 0.857 mol Cl2
calcular masa mol = masa/Mm
masa = 0.857 mol x 71 g/mol
masa = 60.85 g de cloro
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CO2 (Dióxido de carbono)
V = 40 L
P = 778 mmHg = 1.023 atm.
R = 0.0821 ( L atm / mol K)
T = 31 ºC + 273 = 304 K
n = ?
n = 40 L x 1.023 atm
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0.0821 (Latm/mol K) x 304 K
n = 1.639 mol CO2
calcular masa mol = masa/Mm
masa = 1.639 mol x 44 g/mol
Masa = 72.116 g de CO2
Pesa más el CO2 CON 72.116 g con respecto al cloro que pesa 60.85 g
CLORO: Cl2
V = 20 L
P = 800 mmHg = 1.052 atm.
R = 0.0821 ( L atm / mol K)
T = 26 ºC + 273 = 299 K
n = ?
n = 20 L x 1.052 atm
````````````````````````````````````````
0.0821 (Latm/mol K) x 299 K
n = 0.857 mol Cl2
calcular masa mol = masa/Mm
masa = 0.857 mol x 71 g/mol
masa = 60.85 g de cloro
``````````````````````````````````````````````````````````````````````````````````````````````````````
CO2 (Dióxido de carbono)
V = 40 L
P = 778 mmHg = 1.023 atm.
R = 0.0821 ( L atm / mol K)
T = 31 ºC + 273 = 304 K
n = ?
n = 40 L x 1.023 atm
````````````````````````````````````````
0.0821 (Latm/mol K) x 304 K
n = 1.639 mol CO2
calcular masa mol = masa/Mm
masa = 1.639 mol x 44 g/mol
Masa = 72.116 g de CO2
Pesa más el CO2 CON 72.116 g con respecto al cloro que pesa 60.85 g
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