¿Qué cantidad de solvente se necesita para preparar 180g de una solución al 15% en m/m
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10
m = 180 g solución
15% m/m
% m/m = masa soluto x 100
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masa solucion
masa soluto = % m/m x masa solc.
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100
masa soluto = 15 g/g x 180 g
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100
masa soluto = 27 g
m solc. = msoluto + m solvente
m solvente = m soluc - m soluto
m solvente = 180 g - 27 g
m solvente = 153 g de solvente
15% m/m
% m/m = masa soluto x 100
````````````````
masa solucion
masa soluto = % m/m x masa solc.
````````````````````````````
100
masa soluto = 15 g/g x 180 g
``````````````````
100
masa soluto = 27 g
m solc. = msoluto + m solvente
m solvente = m soluc - m soluto
m solvente = 180 g - 27 g
m solvente = 153 g de solvente
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