Question

que bolumen ocupa 45 g de CH4 a 27°C y a 800 Torr

Answer 1

Mm CH4 = 16 g/mol

T = 27 + 273 = 300 K
m = 45 g

MOLES= masa / Mm
moles = 45 g / 16 g/mol = 2.813 mol
P = 800 torr
760 torr ------  1 atm
800 torr ------      x
x = 1.0526 atm

R = 0.0821 (mol x atm/ L x mol)

P x V = n x R x T

V = n x R x T
      ````````````
          P

V = 2.813 mol x 0.0821 (mol x atm/ L x mol) x 300 K
      ``````````````````````````````````````````````````````````````````
                             1.0526 atm

V = 65.82 L