Question

Q(x; y) = 4x2 + 2y2 - xy, para x = 3; y = 4 montase​

Answer 1

Respuesta:

Q(x; y) = 4x² + 2y² - xy

para:

x = 3

y = 4

Sustituir:

$\rm \bold{Q(x; y) = 4(3)^{2} + 2(4)^{2} - (3)(4)}$

Q(x; y) = 4(9) + 2(16) - 12

Q(x; y) = 36 + 32 - 12

Q(x; y) = 68 - 12

Q(x; y) = 56