Question

Pueden ayudarme a resolver esto por favor, es urgente​

Answer 1

1)

$\frac{2x + 3}{ - 5} = \frac{2}{ - 1} \\ - 2x - 3 = - 10 \\ 2x + 3 = 10 \\ 2x = 7 \\ x = \frac{7}{2}$

2)

$\frac{ \sqrt{100} - 4 }{x} = \frac{x}{ - 1} \\ \frac{10 - 4}{x} = - x \\ 6 = - {x}^{2} \\ {x}^{2} = - 6 \\ x = \sqrt{6} i \: \: \: o \: \: \: x = - \sqrt{6} i$

3)

$\frac{ - 4 + {5}^{0} }{3} = \frac{x}{ - 1} \\ - 4 + 1 = - 3x \\ - 3x = - 3 \\ x = 1$

4)

$\frac{ \sqrt{4} }{ {7}^{0} } = \frac{x}{ \frac{1}{2} } \\ 2 = 2x \\ x = 1$

5)

$\frac{x}{ \frac{1}{4} } = \frac{x + 1}{ \frac{3}{4} - \frac{1}{5} } \\ 4x = \frac{x + 1}{ \frac{15 - 4}{20} } \\ 4x = \frac{x + 1}{ \frac{11}{20} } \\ 44x = 20x + 20 \\ 22x = 20 \\ x = \frac{10}{11}$

6)

$\frac{ \frac{2}{4} - \frac{1}{4} }{x + 2} = \frac{ \frac{3}{2} }{2x - 3} \\ \frac{1}{4x + 8} = \frac{3}{4x - 6} \\4x - 6 = 12x + 24 \\ 8x = - 30 \\ x = - \frac{15}{4}$

7)

$\frac{x}{0.2} = \frac{ {( - 0.5)}^{2} }{ \frac{2}{9} } \\ \frac{2x}{9} = 0.05 \\ 2x = 0.45 \\ 2x = \frac{45}{100} \\ x = \frac{9}{40}$

8)

$\frac{ - 5 + 4}{ \sqrt[3]{ - 8} } = \frac{x}{ \sqrt{16} } \\ \frac{ - 1}{ - 2} = \frac{x}{4} \\ 4 = 2x \\x = 2$