Question

procedimiento del problema ​

Answer 1

Respuesta:

x = 1

Explicación paso a paso:

$\frac{1}{x^{2} -x} - \frac{1}{x -1} =0\\\\\frac{1}{x(x-1)} - \frac{1}{x -1} =0\\\\\frac{1}{x-1}(\frac{1}{x} -1)=0\\\\\frac{1}{x} - 1 = 0\\\\1 - x = 0\\\\1 = x\\\\x =1$