Question

PRACTICA REALIZANDO LAS SIGUIENTES OPERACIONES.


a) 10/(20-10) + 4 =

b) -5(-9 + 3 x 4) - 6 =

c)-(3-4÷4) + 3(2-6)=

d) -3[4 +5(-3+ 4)] + 2[64(6-2)] =

e) 2 + 5{4- [5+ (1+2+2)]} =

f) -{-3+ [-7(6-5) + 2 x 3]} - [-6(2-3)] =

Answer 1

Respuesta:

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Explicación paso a paso:

a) 10/(20-10) + 4 =5

$\frac{10}{20 - 10} + 4 \\ 10 \div 10 = 1 \\ 1 + 4 = 5$

b) -5(-9 + 3 x 4) - 6 =-21

$- 5 \times ( - 9 + 12) - 6 \\ - 5 \times 3 - 6 \\ - 15 - 6 \\ - 21$

c)-(3-4÷4) + 3(2-6)=-14

$- (3 - 1) + 3 \times (2 - 6) \\ - 2 + 3 \times ( - 4) \\ - 2 - 3 \times 4 \\ - 2 - 12 \\ - 14$

d) -3[4 +5(-3+ 4)] + 2[64(6-2)] =485

$- 3 \times (4 + 5) + 2 \times (64 \times 4) \\ - 3 \times 9 + 2 \times (64 \times 4) \\ - 27 + 2 \times 256 \\ - 27 + 512 \\ 485$

e) 2 + 5{4- [5+ (1+2+2)]} =-28

$2 + 5 \times (4 - (5 + 5)) \\ 2 + 5 \times (4 - 10) \\ 2 + 5 \times ( - 6) \\ 2 - 5 \times 6 \\ 2 - 30 \\ - 28$

f) -{-3+ [-7(6-5) + 2 x 3]} - [-6(2-3)] =-2

$- ( - 3 + (7 + 2 \times 3)) - ( - 6 \times ( - 1)) \\ - ( - 3 + ( - 7 + 6)) - 6 \\ - ( - 3 - 1) - 6 \\ - ( - 4) - 6 \\ 4 - 6 \\ - 2$