Question

porfavor me ayudan.
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Answer 1

Respuesta:

$p(x.y) = {5x}^{2} - 2xy \: + {y}^{2} \: - {4x}^{2} \: + xy \: + {2y}^{2} \: - {x}^{2} \: + 3xy \: - {5y}^{2}$

$p(x.y) = {0x}^{2} \: + 2xy \: - {2y}^{2}$

$p(x.y) = 2xy \: - {2y}^{2}$