Question

PORFAVOR , DOY CORONITA, resolver ecuaciones de segundo grado usando el metodo de factorizacion.
1️⃣ -x²+5x=0
2️⃣ 2x²-32=0
3️⃣ x²+4x-21=0
4️⃣ x²-12x+36=0
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Answer 1

Respuesta

1.  *(-1*x+5)*x=0  

(-1*x+5)=0  

-1*x+5=0  

-1*x=-5  

1*x=5  

x=0  

x=0

2.  

2*x^2=32  

1*x^2=16  

x=+-*16^0.5  

x_1=16^0.5  

1*x_1=4  

x_2=-1*16^0.5  

1*x_2=-4

3.

 

1*x^2+4*x=21  

1*x^2+4*x+(2)^2=2^2+21  

1*x^2+4*x+(2)^2=4+21  

1*x^2+4*x+(2)^2=4+21  

1*(1*x+(2))^2=25  

1*x+(2)=+-*25^0.5  

1*x_1+(2)=25^0.5  

1*x_1+2=25^0.5  

1*x_1+2=5  

1*x_1=3  

1*x_2+(2)=-1*25^0.5  

1*x_2+2=-1*25^0.5  

1*x_2+2=-1*5  

1*x_2=-7

4.

1*x^2+-12*x=-36  

1*x^2+-12*x+(-6)^2=-6^2+-36  

1*x^2+-12*x+(-6)^2=36+-36  

1*x^2+-12*x+(-6)^2=36+-36  

1*(1*x+(-6))^2=0  

1*x+(-6)=1*0^0.5  

1*x+-6=0^0.5  

1*x+-6=0  

1*x=6  

Explicación paso a paso:

espero te sirva :)