Question

porfavor ayudenme encerio lo necesito​

Answer 1

Explicación paso a paso:

• Las ecuaciones cuadráticas de la forma
• x²-c²= 0 se resuelven así: x= ±√c

1)

$x {}^{2} - 25 = 0 \\ x {}^{2} = 25 \\ x =± \sqrt{25} \\ x = ±5\\ \boxed{x_1 - 5 =0 ; \: x_1 = 5 } \\ \boxed{x_2 + 5 = 0 ; \: x_2 = - 5}$

2)

$x {}^{2} = 100 \\ \sqrt{ x {}^{2} } = ± \sqrt{100} \\ x = ±10 \\ \boxed{ x _ 1 - 10 = 0 \: ; \: \: x_1 = 10} \\ \boxed{ x _ 2 + 10 = 0 \: ; \: \: x_2 = - 10}$

3)

${x}^{2} - 49 = 0 \\ {x}^{2} = 49 \\ \sqrt{ {x}^{2} } = ± \sqrt{49} \\ x = ±7 \\ \boxed{x_1 - 7 =0 ; \: x_1 = 7 } \\ \boxed{x_2 + 7 = 0 ; \: x_2 = - 7}$

4)

${x}^{2} = 1 \\ \sqrt{x {}^{2} } = ±\sqrt{1} \\ x =±1 \\ \boxed{x_1 -1 =0 ; \: x_1 = 1 } \\ \boxed{x_2 + 1 = 0 ; \: x_2 = - 1}$

5)

${x}^{2} - 64 = 0 \\ \sqrt{x {}^{2} } = ±\sqrt{64} \\ x =±8 \\ \boxed{x_1 - 8 =0 ; \: x_1 = 8 } \\ \boxed{x_2 + 8 = 0 ; \: x_2 = - 8}$

6)

${x}^{2} - 121 = 0 \\ \sqrt{x {}^{2} } = ±\sqrt{121} \\ x =±11 \\ \boxed{x_1 - 11 =0 ; \: x_1 = 11 } \\ \boxed{x_2 + 11 = 0 ; \: x_2 = - 11}$

7)

${x}^{2} - 144 = 0 \\ \sqrt{x {}^{2} } = ±\sqrt{144} \\ x =±12 \\ \boxed{x_1 - 12 =0 ; \: x_1 = 12 } \\ \boxed{x_2 + 12 = 0 ; \: x_2 = - 12}$

8)

${x}^{2} - 36 = 0 \\ \sqrt{x {}^{2} } = ±\sqrt{36} \\ x =±6 \\ \boxed{x_1 - 6 =0 ; \: x_1 = 6 } \\ \boxed{x_2 + 6 = 0 ; \: x_2 = - 6}$

9)

${x}^{2} - 169 = 0 \\ \sqrt{x {}^{2} } = ±\sqrt{169} \\ x =±13 \\ \boxed{x_1 - 13 =0 ; \: x_1 = 13 } \\ \boxed{x_2 + 13 = 0 ; \: x_2 = - 13}$

10)

${x}^{2} - 400 = 0 \\ \sqrt{x {}^{2} } = ±\sqrt{400} \\ x =±20 \\ \boxed{x_1 - 20 =0 ; \: x_1 = 20 } \\ \boxed{x_2 +20 = 0 ; \: x_2 = - 20}$

Espero que sea de tu ayuda

Saludos :)