Question

porfavor ayúdeme a desarrollarlo le doy 10 puntos PORFAVOR AYUDENME ​

Answer 1

Respuesta:

7

I. 7x

II. x

III. $7x^{2}+4y^{2}+x+6y$

IV.   - $x^{2} +4y^{2}+x+6y$

V. $x^{2} +4y^{2} +x+6y$

8

I.  -7x

II. 7x

III.$z^{2}$

IV.

$2x+z^{2}$

Explicación paso a paso:

Answer 2

Explicación paso a paso:

7) I. (3x) + (4x) = 7x

II. (-3x) + (4x) = x

III. (4x^2 + 6y + 3y^2) + (x + 3x^2 + y^2)

= (4x^2 + 3x^2) + (6y) + (x) + (3y^2 + y^2)

= 7x^2 + x + 6y + 4y^2

= x * (7x + 1) + 2y * (3 + 2y)

IV. (-4x^2 + 6y + 3y^2) + (x + 3x^2 + y^2)

= (-4x^2 + 3x^2) + (x) + (3y^2 + y^2) + 6y

= - x^2 + x + 4y^2 + 6y

= x * (-x + 1) + 2y * (2y + 3)

V. (4x^2 + 6y + 3y^2) + (x - 3x^2 + y^2)

= (4x^2 - 3x^2) + (x) + (3y^2 + y^2) + 6y

= x^2 + x + 4y^2 + 6y

= x * (x + 1) + 2y * (2y + 3)

8) I. (-3x) - (4x) = (-7x)

II. (3x) - (-4x) = (3x) + (4x) = 7x

III. (x + y + 2z^2) - (x + y + z^2)

= x+ y + 2z^2 - x - y - z^2

= (x - x) + (y - y) + (2z^2 - z^2)

=z^2

IV. (x + y + 2z^2) - (-x + y + z^2)

= x + y + 2z^2 + x - y - z^2

= (x + x) + (y - y) + (2z^2 - z^2)

= 2x + z^2