Question

porfaaa es urgente
(x+1)(x+2)=6​

Answer 1

Respuesta:

$(x + 1)(x + 2) = 6 \\ {x}^{2} + 2x + x + 2 = 6 \\ {x}^{2} + 3x + 2 = 6 \\ {x}^{2} + 3x + 2 - 6 = 0 \\ {x}^{2} + 4x - x - 4 = 0 \\ x(x + 4) - (x + 4) = 0 \\ (x + 4)(x - 1) = 0 \\ x + 4 = 0 \\ x - 1 = 0 \\ x = - 4 \\ x = 1 \\ soluciones = \\ x = - 4 \\ x = 1$