Question

porfa la tareas es para ahorita ​

Answer 1

Explicación paso a paso:

a)

$\sqrt[x]{ {(3 + 6)}^{4} } = 9$

${(3 + 6)}^{4} = {9}^{x}$

${9}^{4} = {9}^{x} \to \: x = 4$

b)

$\sqrt[3]{ {6}^{x} \times 27 } =36 \times 3 = 108$

$\sqrt[3]{ {6}^{x} \times {3}^{3} } = {6}^{2} \times 3$

${6}^{x} \times {3}^{3} = {( {6}^{2} \times 3 })^{3}$

${6}^{x} \times {3}^{3} = {6}^{6} \times {3}^{3} \to \: x = 6$

c)

$\sqrt[4]{ {(4 + 2})^{x} } = 36$

$\sqrt[4]{ {6}^{x} } = {6}^{2}$

${6}^{x} = {6}^{2 \times 4} \to \: x = 8$