Matemáticas, pregunta formulada por twiceeefree, hace 1 mes

Porfa es pará hoy :((

Resuelve las siguientes sumas de fracciones:

1/5+1/6=
1/3+1/4=
2/5+2/3=
1/8+1/9=
1/6+2/7=
4/11+2/9=
8/13+1/6=
1/8+2/3=​​

Respuestas a la pregunta

Contestado por yanethfortanell5
0

Respuesta:

11/30

7/12

16/15

17/72

19/42

58/99

61/78

19/24

Contestado por metanight2002
0

\bold{ a) \frac{1}{5} + \frac{1}{6} }

\rightarrow \frac{1}{\bold{5}}+\frac{1}{\bold{6}} = \frac{}{\bold{ 5 \times 6}}

\rightarrow \frac{1}{\bold{5}}+\frac{1}{\bold{6}} = \frac{}{\bold{ 30 }}

para~~\frac{~}{30} ~~ y~~\frac{1}{5} :~~ \bold{30 \div 5 =6}

para~~\frac{~}{30} ~~ y~~\frac{1}{6} :~~ \bold{30 \div 6 =5}

para~~\frac{1}{5} :~~ \bold{1 \times 6=6}

para~~\frac{1}{6} :~~ \bold{1 \times 5=5}

\rightarrow \frac{1}{5}+\frac{1}{6} = \frac{6+5}{30}

\rightarrow \bold{\underline{\frac{1}{5}+\frac{1}{6} = \frac{11}{30}}}

\bold{ b) \frac{1}{3} + \frac{1}{4} }

\rightarrow \frac{1}{\bold{3}}+\frac{1}{\bold{4}} = \frac{}{\bold{ 3 \times 4}}

\rightarrow \frac{1}{\bold{3}}+\frac{1}{\bold{4}} = \frac{}{\bold{ 12 }}

para~~\frac{~}{12} ~~ y~~\frac{1}{3} :~~ \bold{12 \div 3 =4}

para~~\frac{~}{12} ~~ y~~\frac{1}{4} :~~ \bold{12 \div 4 =3}

para~~\frac{1}{3} :~~ \bold{1 \times 4=4}

para~~\frac{1}{4} :~~ \bold{1 \times 3=3}

\rightarrow \frac{1}{3}+\frac{1}{4} = \frac{4+3}{12}

\rightarrow \bold{ \underline{\frac{1}{3}+\frac{1}{4} = \frac{7}{12}}}

\bold{ c) \frac{2}{5} + \frac{2}{3} }

\rightarrow \frac{2}{\bold{5}}+\frac{2}{\bold{3}} = \frac{}{\bold{5 \times 3}}

\rightarrow \frac{2}{\bold{5}}+\frac{2}{\bold{3}} = \frac{}{\bold{ 15 }}

para~~\frac{~}{15} ~~ y~~\frac{2}{5} :~~ \bold{15 \div 5 =3}

para~~\frac{~}{15} ~~ y~~\frac{2}{3} :~~ \bold{15 \div 3 =5}

para~~\frac{2}{5} :~~ \bold{2 \times 3=6}

para~~\frac{2}{3} :~~ \bold{2 \times 5=10}

\rightarrow \frac{2}{5}+\frac{2}{3} = \frac{6+10}{15}

\rightarrow \bold{ \underline{\frac{2}{5}+\frac{2}{3} = \frac{16}{15}}}

\bold{ d) \frac{1}{8} + \frac{1}{9} }

\rightarrow \frac{1}{\bold{8}}+\frac{1}{\bold{9}} = \frac{}{\bold{8 \times 9}}

\rightarrow \frac{1}{\bold{8}}+\frac{1}{\bold{9}} = \frac{}{\bold{ 72 }}

para~~\frac{~}{72} ~~ y~~\frac{1}{8} :~~ \bold{72 \div 8 =9}

para~~\frac{~}{72} ~~ y~~\frac{1}{9} :~~ \bold{72 \div 9 =8}

para~~\frac{1}{8} :~~ \bold{1 \times 9=9}

para~~\frac{1}{9} :~~ \bold{1 \times 8=8}

\rightarrow \frac{1}{8}+\frac{1}{9} = \frac{9+8}{72}

\rightarrow \bold{ \underline{\frac{1}{8}+\frac{1}{9} = \frac{17}{72}}}

\bold{ e) \frac{1}{6} + \frac{2}{7} }

\rightarrow \frac{1}{\bold{6}}+\frac{2}{\bold{7}} = \frac{}{\bold{6 \times 7}}

\rightarrow \frac{1}{\bold{6}}+\frac{2}{\bold{7}} = \frac{}{\bold{ 42 }}

para~~\frac{~}{42} ~~ y~~\frac{1}{6} :~~ \bold{42 \div 6 =7}

para~~\frac{~}{42} ~~ y~~\frac{2}{7} :~~ \bold{42 \div 7 =6}

para~~\frac{1}{6} :~~ \bold{1 \times 7=7}

para~~\frac{2}{7} :~~ \bold{2 \times 6=12}

\rightarrow \frac{1}{6}+\frac{2}{7} = \frac{7+12}{42}

\rightarrow \bold{ \underline{\frac{1}{8}+\frac{1}{9} = \frac{19}{42}}}

\bold{ f) \frac{4}{11} + \frac{2}{9} }

\rightarrow \frac{4}{\bold{11}}+\frac{2}{\bold{9}} = \frac{}{\bold{11 \times 9}}

\rightarrow \frac{4}{\bold{11}}+\frac{2}{\bold{9}} = \frac{}{\bold{ 99 }}

para~~\frac{~}{99} ~~ y~~\frac{4}{11} :~~ \bold{99 \div 11 =9}

para~~\frac{~}{99} ~~ y~~\frac{2}{9} :~~ \bold{99 \div 9=11}

para~~\frac{4}{11} :~~ \bold{4 \times 9=36}

para~~\frac{2}{9} :~~ \bold{2 \times 11=22}

\rightarrow \frac{4}{11}+\frac{2}{9} = \frac{36+22}{99}

\rightarrow \bold{ \underline{\frac{4}{11}+\frac{2}{9} = \frac{58}{99}}}

\bold{ g) \frac{8}{13} + \frac{1}{6} }

\rightarrow \frac{8}{\bold{13}}+\frac{1}{\bold{6}} = \frac{}{\bold{13 \times 6}}

\rightarrow \frac{8}{\bold{13}}+\frac{1}{\bold{6}} = \frac{}{\bold{78}}

para~~\frac{~}{78} ~~ y~~\frac{8}{13} :~~ \bold{78 \div 13 =6}

para~~\frac{~}{78} ~~ y~~\frac{1}{6} :~~ \bold{78 \div 6 =13}

para~~\frac{8}{13} :~~ \bold{8 \times 6=48}

para~~\frac{1}{6} :~~ \bold{1 \times 13=13}

\rightarrow \frac{8}{13}+\frac{1}{6} = \frac{48+13}{78}

\rightarrow \bold{ \underline{\frac{8}{13}+\frac{1}{6} = \frac{61}{78}}}

\bold{ h) \frac{1}{8} + \frac{2}{3} }

\rightarrow \frac{1}{\bold{8}}+\frac{2}{\bold{3}} = \frac{}{\bold{8 \times 3}}

\rightarrow \frac{1}{\bold{8}}+\frac{2}{\bold{3}} = \frac{}{\bold{24}}

para~~\frac{~}{24} ~~ y~~\frac{1}{8} :~~ \bold{24 \div 8 =3}

para~~\frac{~}{24} ~~ y~~\frac{2}{3} :~~ \bold{24 \div 3 =8}

para~~\frac{1}{8} :~~ \bold{1 \times 3=3}

para~~\frac{2}{3} :~~ \bold{2 \times 8=16}

\rightarrow \frac{1}{8}+\frac{2}{3} = \frac{3+16}{24}

\rightarrow \bold{ \underline{\frac{1}{8}+\frac{2}{3} = \frac{19}{24}}}

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