Question

PORFA con prodecedimiento
(es para un amigo) xd

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Answer 1

$a) \frac{2}{3} + \frac{5}{6} + \frac{3}{12} = \frac{8}{12} + \frac{10}{12} + \frac{3}{12} = \frac{8 + 10 + 3}{12} = \frac{21}{12} = \frac{7}{4}$

$b) \frac{2}{5} + \frac{1}{10} + \frac{7}{20} = \frac{8}{20} + \frac{2}{20} + \frac{7}{20} = \frac{8 + 2 + 7}{20} = \frac{17}{20}$

$c) \frac{4}{5} + \frac{2}{15} + \frac{9}{20} = \frac{48}{60} + \frac{8}{60} + \frac{27}{60} = \frac{48 + 8 + 27}{60} = \frac{83}{60}$

$d) \frac{4}{9} + \frac{2}{3} + \frac{5}{6} = \frac{8}{18} + \frac{12}{18} + \frac{15}{18} = \frac{8 + 12 + 15}{18} = \frac{35}{18}$

$e) \frac{3}{4} - \frac{5}{7} = \frac{21}{28} - \frac{20}{28} = \frac{21 - 20}{28} = \frac{1}{28}$

$f)2 \frac{1}{2} + \frac{4}{5} = \frac{5}{2} + \frac{4}{5} = \frac{25}{10} + \frac{8}{10} = \frac{25 + 8}{10} = \frac{33}{10}$