Question

porfa ayudenme tengo hasta las 12 para entregar esa tarea

Answer 1

Explicación paso a paso:

${a}^{2} + {b}^{2} + {c}^{2} + 21 = 2a + 4b + 8c$

${(a - 1)}^{2} + {(b - 2)}^{2} + {(c - 4)}^{2} = 0$

${(a - 1)}^{2} = 0 \\ {(b - 2)}^{2} = 0 \\ {(c - 4)}^{2} = 0$

$a = 1 \\ b = 2 \\ c = 4$

${c}^{ {b}^{ - a} } = {4}^{ {2}^{ - 1} }$

${4}^{ {2}^{ - 1} } = {4}^{ { \frac{1}{2} }} = \sqrt{4} = 2$