Question

porfa ayudenme en estos ejercicios de quimica (formula mínima) C=40% O=53,4% H=6,6% (formula molecular) C=61,0% O=27,12% H=11,88%

Answer 1

C: 40 g / 12 g/ mol = 3.33 mol
H: 6.6 g / 1 g/mol = 6.6 mol
O: 53.4 g/16 g/mol = 3.33 mol

dividir cada elemento entre el menor de los resultados

C: 3.33 mol / 3.33 mol = 1
H: 6.6 mol / 3.33 mol = 2
O: 3.33 mol / 3.33 mol = 1

FE: CH2O

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C: 61 g/ 12 g/mol = 5.08 mol
H: 11.88 g/ 1 g/mol = 11.88 mol
O: 27.12 g/ 16 g/mol = 1.69 mol

dividir

C: 5.08 mol / 1.69 mol = 3
H: 11.88 mol / 1.69 mol = 7
O: 1.69 mol / 1.69 mol = 1

FE: C3H7O